Question

(43) Express escape velocity in terms of g
and R.​

Answer 1

Explanation:

the energy required to escape the Earth's gravitational field is GMm / r, a function of the object's mass (where r is the radius of the Earth, G is the gravitational constant, and M is the mass of the Earth, M = 5.9736 × 1024 kg). ... It is equal to G = 6.674 × 10-11 N·m²/kg² .

Answer 2

$\pmb{\bf{\underline{Answer~➛}}}$

$Escape \: Velocity \: ( \: V _{esc}) = \sqrt{ \frac{2GM}{R} } \\ \\ Now \: , \: g \: = \frac{ GM}{R ^{2} } \\ \\ ∵ \: GM \: = gR ^{2} \\ \\ ∵ \: V _{esc} = \sqrt{ \frac{ 2gR^{2}}{R} } = \sqrt{2gR}$

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