Question

43. In an electron gun of a TV set an electron with an initial speed of 1000 m/s enters a region where it is electrically
accelerated it emerges out of this region after 1 micro second with a speed of 4*10^5 m/s Maximum Length (in meters)
of electron gun and acceleration (in m/s^2) of the electron are?
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Answer 1

Answer:

initial velocity = 1000m/s

final velocity = 400000m/s

time = 1mc or 0.000001s or 1/1000000s

therefore, acceleration = (400000-1000)/(1/1×10⁶)

= 399000 × 10⁶

= 3.99 × 10¹¹ m/s²

therefore, distance = ut + ½at²

= 1000/10⁶ + 3.99×10¹¹/10⁶

= 1/10³ + 3.99×10⁵

= 1+3.99×10⁸/10³

= 3.99000001×10⁸/10³

= 3.99000001×10⁵

= 399000.001 m or 399000m(approx)

Hope it helped :)