432 735 357 287 259 389
if 15 is subtracted from each of the above numbers after arranging the digits in reverse order with the number,then the sum of digits of how many of them will be
multiple of 32
One
Two
Three
Four
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Answers
Answer:
three
Step-by-step explanation:
QUE:432 735 357 287 259 389
if 15 is subtracted from each of the above numbers after arranging the digits in reverse order with the number,then the sum of digits of how many of them will be multiple of 3?
ANS:432-15,735-15, 357-15, 287-15, 259-15, 389 -15
now 417,720,342,272,244,374
reverse order 714,027,243,272,442,473(here note divisible by 3.so sum of all the digits is important.if suppose you did not reverse the order tat also gives the answer)
then ans will be (720,342,417 ) option C three
Given: 432 735 357 287 259 389
If 15 is subtracted from each of the above numbers after arranging the digits in reverse order with the number.
To find: The sum of digits of how many of them will be multiple of 32.
Solution: The sum of digits of none of them will be multiple of 32.
According to the question, first, the digits of all the numbers must be arranged in the reverse order. Thus, 432 becomes 234, 735 becomes 537, 357 becomes 753, 287 becomes 782, 259 becomes 952 and 389 becomes 983.
Then, 15 is subtracted from all these numbers. Thus, 234 becomes 219, 537 becomes 522, 753 becomes 738, 782 becomes 767, 952 becomes 937 and 983 becomes 968.
Now, the sum of digits of each of them is 12, 9, 18, 20, 19 and 23. None of these numbers are a multiple of 32.
Therefore, the sum of digits of none of them will be multiple of 32.