Question

44. A bag contains 50 p, 25p and 10 p coins in the ratio 5:9: 4, amounting to Rs 206. Find the number of coins of each type. A) 200, 360, 160 B) 300, 460, 560 C) 100 260 300 D) 400, 360, 260​

Answer 1

Answer:

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Answer 2

Answer:

A money bag contains 50p,25p and 10p coins in the ratio 5:9:4 and the total amount is Rs.206. How many individual coins are there in each type?

Let the number of coins of 50p, 25p and 10p denominations are 5X, 9X and 4X respectively.

To get the value of Amount from each denomination multiply it with number of coins.

Thus, Amount of 50p = 5X * 50 = 250X … …. (1)

Amount of 25p = 9X * 25 = 225X … …. (2)

And Amount of 10p = 4X * 10 = 40X … …. (3)

Total of these is given to be Rs 206 = 206 x 100 Paise = 20600

Thus, we get the equation as,

250X + 225X + 40X = 20600

515X = 20600

X = 20600/515 = 40

Putting this value in (1), (2) and (3) we have,

5 x 40 = 200 Coins of 50p amounting to Rs 100

9 x 40 = 360 Coins of 25p amounting to Rs 90

4 x 40 = 160 Coins of 10p amounting to Rs 16

Total 720 coins amounting Rs 206