Question

44. The 10th term of a GP whose 8th term is 192 and the common ratio is 3 is

A. 1782
B. 1738
C. 1728
D. 1278​

Answer 1

Answer:

T10 = 1728 option c

Step-by-step explanation:

nth term of a GP is Tn = ar^n-1

8 th term of a GP is T8 = ar^7 = 192

and common ratio r = 3

so, a (3)^7 = 192

a = 192/ (3)^7

10th term of a GP is T10 = ar^9 = (192/ (3)^7) * (3)^9

T10 = 1728 option c