Question

44. The adjoining figure shows a block of mass 10 kg
connected to free end of a rope of mass 10kg and length
10m. The tension of the rope at point A TS
(8 = 10 m/s2)

Answer 1

The tension at point A is 70 N.

Explanation:

Given data:

Mass of block = 10 Kg

Mass at the end point of rope = 10 Kg

Length of rope = 10 m

Solution:

This problem can be solved bu=y using unitary method. i.e.

The distance at point A = 10 - 3 = 7 m

As we can see that

Tension on 1 m = 10 N

Tension on 10 m = 100 N

Similarly

Tension on 7 m = 70 N

Thus the tension at point A is 70 N.

Also learn more

The length of an elastic string is X m when the tension is 8N and Y m when the tension is 10 N .What is the length in metres when the tension is 18 N?

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Answer 2

Answer:

130 N

Explanation:

At the end of the rope which is connected to the ceiling, the effective mass is 20 kg. as we go 1m downwards, 1 kg decreases. That is, at the point A, the effective mass is 13kg (20m - 7m). so the tension is 13 kg * 10m/s2 = 130 N.