Question

45+3{34-18-14}/3[17+3*4-(2*7)] ​

Answer 1

Answer:

If the question is $\frac{[45 + 3(34 - 18 - 14)]}{3[17 + 3x4 - (2x7)]}$, then = $1\frac{2}{15}$

And if the question is $45 + \frac{3(34 - 18 - 14)}{3[17 + 3x4 - (2x7)]}$  then = $45\frac{2}{15}$

Step-by-step explanation:

If the question is $\frac{[45 + 3(34 - 18 - 14)]}{3[17 + 3x4 - (2x7)]}$

Then, the result = $\frac{[45 + 3x2]}{3x15}$ =$\frac{51}{3x15}$ =$\frac{17}{15}$ = $1\frac{2}{15}$

And if the question is $45 + \frac{3(34 - 18 - 14)}{3[17 + 3x4 - (2x7)]}$ = 45 + $\frac{2}{15}$ =$45\frac{2}{15}$

Answer 2

$\huge\b{Answer:}}$

Question:

45+3{34-18-14}/3[17+3*4-(2*7)].

Explanation:

45+3[34−18−14]÷3[17+3×4−(2×7)] ,

⇒45+3[34−32]÷3[17+12−14],

→45+$\large\bold{\frac{3*2}{3*15}}$,

→45+$\large\bold{\frac{2}{15}}$,

→675+$\large\bold{\frac{2}{15}}$,

→$\huge\bold{\frac{677}{15}}$.