45(a+b)^2(a-b)-10(a+b)(a-b)^2 factorise
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45(a+b)²(a-b)-10(a+b)(a-b)²
=(a+b)(a-b){45(a+b)-10(a-b). { taking (a+b)(a-b) as common}
=(a+b)(a-b)(45a+45b-10a+10b)
=(a+b)(a-b)(35a+55b)
=(a+b)(a-b)5(7a+11b)
this is what I think...
=(a+b)(a-b){45(a+b)-10(a-b). { taking (a+b)(a-b) as common}
=(a+b)(a-b)(45a+45b-10a+10b)
=(a+b)(a-b)(35a+55b)
=(a+b)(a-b)5(7a+11b)
this is what I think...
rishi1803:
is it correct?
We can take 5 common along with (a+b)(a-b)
ya
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