Question

45. A block of mass 5 kg is dragged along a level rough
surface having coefficient of friction (u = 0.8) by a
hanging block of mass 10 kg as shown in the figure.
The tension in the string is (g = 10 m/s2)

(1) 40 N
(3) 60 N
(2) 100 N
(4) 75N​

Answer 1

answer : option (3) 60N

Let T is tension in string, f is frictional force acting between block and rough surface.

f = μN , where N is normal reaction between block and surface.

= 0.8 × mg = 0.8 × 5kg × 10m/s²

= 40N

for block of mass 5 kg,

T - f = ma

⇒T - 40 = 5a .......(1)

for block of mass 10kg,

Mg - T = Ma

⇒10kg × 10m/s² - T = 10a

⇒100 - T = 10a ........(2)

from equations (1) and (2) we get,

100 - 40 = 5a + 10a

⇒60 = 15a

⇒a = 4 m/s²

from equation (1),

T = 40 + 4 × 5 = 60N

also read similar questions : A block of mass 10 kg is kept on a fixed rough(u=0.8) inclined plane of angle of inclination 30 degree the frictional fo...

https://brainly.in/question/11045079

A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to...

https://brainly.in/question/8443448

Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

(3) 60 N