45
(d)
The perimeter of a rectangle is 30 m and the
ratio between length and breadth is 7:3. Find
(c) 449 m2
the area of the rectangle,
(a) 46.55 m2
(C) 45.25 m2
(b) 48.50 m2
(d) 47.25 m2
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Answers
Gɪᴠᴇɴ :-
The perimeter of a rectangle is 30 m and the ratio between length and breadth is 7:3.
ᴛᴏ ғɪɴᴅ :-
- Area of Rectangle
sᴏʟᴜᴛɪᴏɴ :-
Let the ratio of length and breadth be 7x : 3x
We know that,
➦ Perimeter of Rectangle = 2(l + b)
➤ According to Question :-
➭ 2( l + b) = 30
➭ 2(7x + 3x) = 30
➭ 2(10x) = 30
➭ 10x = 30/2
➭ 10x = 15
➭ x = 15/10
➭ x = 1.5
Then,
- Length = 7x = 7×1.5 = 10.5m
- Breadth = 3x = 3×1.5 = 4.5
Now,
We know that,
➦ Area of Rectangle = length × breadth
➭ l × b
➭ 10.5 × 4.5
➭ 47.25 m²
Hence,
- Area of Rectangle = 47.25m²
Therefore,
- Option(d) 47.25m² is correct
Correct Question :
The perimeter of a rectangle is 30 m and the
ratio between length and breadth is 7:3. Find
the area of the rectangle,
(a) 46.55 m2
(C) 45.25 m2
(b) 48.50 m2
(d) 47.25 m2
Solution :
Given ratio of length :Breadth of rectangle = 7:3
Then, let the length of rectangle be 7x and the breadth be 3x.
Now, according to the question
Perimeter of rectangle = 2×(l + b)
30 = 2×(7x + 3x)
30 = 2×10x
30 = 20x
3/2 = x
1.5 = x
Now,
Length of rectangle = 7x = 7×1.5 = 10.5 m
Breadth of rectangle = 3x = 3×1.5 = 4.5 m
Therefore,
Area of the rectangle = l × b
= 10.5 × 4.5 m²
= 47.25 m².