Question

45. How many numbers between 1000 and 10000 can be formed with the digits 0,1,2,3,4 each digit
occurring only once?​

Answer 1

Answer:

Hence the total number lying between 100 and 1000 which can be formed with digits 0, 1, 2, 3, 4, 5, 6, 7 are 294 numbers i.e. 8P3−7P2.

Answer 2

Answer:

total 96number.

Step-by-step explanation:

$(4)(4)(3)(2) = 96$

in 1st box u can fill only 4 letters. becz.u can't fill there 0

in 2nd box u fill 5 numbers but repetition is not allowed so u fill 5-1=4digit

in 3rd box u fill 5-2=3

in 4rth box u fill 5-3=2

so by fundamental principle of multiplicity we get

4*4*3*2=96. digits.