45 is subtracted from a number of two digits, then the digits of the number change their positions among themselves. The number digit of the number is 5 less than the tens digit. What is the original number?
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Let the no. be 10x+y
10x+y-45=10y+x
=)9x-9y=45
=)x-y=5
y+5=x
=)x-y=5
Since both the equations are the same, the no. is 0.
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