Question

Amit is standing at the origin and equidistant from rohit and sumit if rohit is standing on y axis. find the distance between rohit and sumit
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Answer 1

The distance between rohit and sumit is $2\sqrt 2$

• Given,
• Amit is standing at the origin (0,0) and
• equidistant from rohit and sumit
• rohit is standing on y axis
• considering sumit is standing on x axis
• assuming equidistant point be (2,2)
• using distance formula, we get,
• $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\(x_1,y_1)=(0,0)\\\\(x_2,y_2)=(2,2)\\\\d=\sqrt{(2-0)^2+(2-0)^2}\\\\=\sqrt{2^2+2^2} \\\\=\sqrt{8} \\\\=2\sqrt{2}$
• Hence the distance between rohit and sumit is $2\sqrt 2$

Answer 2

Distance from Rohit and Sumit varies from zero to 2a units.

Step-by-step explanation:

Given that Sumit and Rohit are equidistant from Amit who is standing at origin (0,0).

Now, Rohit is standing on the y-axis and the position of Sumit is unknown.

If Rohit is at a units distance from Amit and then Sumit is also a units distant from Amit.

So, the position of Rohit is (0,a).

Now, the position of Sumit can be anywhere on the circumference of the circle made with origin(0,0) as the center and a units as the radius.

Therefore, the distance between Rohit and Sumit will be minimum which is zero, when the position of Rohit and Sumit coincide and that will be maximum, which is 2a units, when the position of Sumit is a units distant from Amit (0,0) on the y-axis at point (0,-a). (Answer)