45°
(2x - 50
80°
X
115°
X
(1)
1. Find the value of x in each of the following diagrams:
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i) Sum of exterior angle is equal to sum of opposite interior angles,
So,
115° = 2x -5° + x
115° = 3x - 5°
3x = 115° + 5°
3x = 120°
x = 120° / 3
x = 40°
ii) Two angles of a triangle = 80° and x°
Third angle = 45° (alternate angles)
Sum of all angles of a triangle = 180°
So,
80° + x + 45° = 180°
125° + x = 180°
x = 180° - 125°
x = 55°
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