Question

450In space of horizontal EF (E=(mg)q) exist as shown in figure and amass m attached at the end of a light rod. If mass m is released from theposition shown in figure find the angular velocity of the rod when itpasses through the bottom most position​

Answer 1

Answer:

Explanation:

=> Here, In space of horizontal EF (E=(mg)q) exist and mass m attached at the end of a light rod.

=> ∴ E = mg / q

=> r = l sinθ

=> θ = 45⁰

angular velocity of the rod ω = ?

=> q*E = M*ω²*r

=> q*Mg/q = M*ω²*l sinθ  [But θ = 45⁰]

=> g = ω²* l sin 45⁰  

=> ω = √2g/l

Thus,  the angular velocity of the rod when it passes through the bottom most position​ is √2g/l.