Chemistry, asked by madhureddy7671, 1 year ago

46 g of a dibasic acid is completely neutralized with 100 ml n/10

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Answered by Anonymous
1
Dibasic acid (AH2) reacts with 100 mL of N10 NaOH.100 mL (0.1 L) of N10 NaOH = 0.1×110=0.01 moles of NaOH0.01 moles of NaOH completely neutrilize the dibasic acid.So, number of moles of AH2 = 0.012 = 0.005 molesMass of 0.005 moles of AH2=0.45 gSo, 1 mole of AH2=0.450.005×1=90 gMolecular weigth of dibasic acid = 90 g.
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