Physics, asked by sashdi8036, 1 year ago

460 j of energy is added to 30g sample of water at 10oc. What will be its final temperature?

Answers

Answered by manoranjanphy1

0

Explanation:

H = M S ∆T

460 = 30/1000 x 4200 x (T-10)

460 = 3 x 42 x (T -10)

460 = 126T - 1260

1720 = 126T

T = 1720/ 126 = 13.65⁰C

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