Question

47) a can finish a work in 18 days and b can do the same work in 15 days. B worked for 10 days and left the job. In how many days a alone can finish the remaining work?

Answer 1

let amount of work finished by a and b in one day be a and b respectively
therefore,total work to be completed is
18a=15b
therefore,6a=5b
B works for 10days
total work done=10b
work yet to be completed is 15b-10b=5b=6a
therefore,A will require 6 days