Question

47) A packet is dropped from a balloon which is going
upwards with the velocity 12 m/s, the velocity of the
packet after 2 seconds will be
(a) -12 m/s (b) 12m/s (c) -7.6m/s (d) 7.6m/s​

Answer 1

Answer:

d) 7.6 m/s

Explanation:

v = u + gt

= -12 + 9.8 × 2

= -12 + 19.6

= 7.6 m/s

Answer 2

Answer:d)7.6m/s

Explanation:Here, acceleration is always negative as body is moves against accln due to gravity....

Using 2nd kinematical eqn.,

H=ut + 1/2at2

H=12×2 - 1/2×9.8×2×2

H=24-19.6

H=4.4m i.e s=4.4m

Put this value in 3rd kinamatical eqn we get ,,

v2=u2 + 2as

v2=12×12 +2×9.8×4.4

v2=144-86.24

v2=57.76

V=7.6m/s