Question

47.

Five kg of air is heated at constant volume. The temperature of air increases from 300k to 340k. if the specific heat at constant volume is 0.169 k cal/kg.. find the amount of heat absorved. 1) 40k cal

2) 20 kcal

3) 33.8k cal

4) 10k cal​

Answer 1

Answer:

The amount of heat absorbed = 33.8 k cal.

Explanation:

Given:

Five kg of air [m] is heated at constant volume. The temperature [T] of air increases from 300k to 340k. if the specific heat [c] at constant volume is 0.169 k cal/kg.

Soln:

Heat energy, Q=mcΔT

Q = 5 x 0.169 x (340-300)

= 5 x 0.169 x 40

Q = 33.8