Chemistry, asked by vinaypratap45, 9 months ago

47. The number of optically active products obtained from
the complete ozonolysis of the given compound is :
(IIT 2012
CH3
H
CH3-CH=CH-C-CH=CH-C-CH=CH-CH
Н
CH3
(a) o
(c) 2
(b) 1
(d) 4​

Answers

Answered by Anonymous
5

Answer:

hey mate

Explanation:

(a) 0 is The Correct Option

Becuase on Ozonolysis We Get 2 Compound

2CH3-CHO and 2CHO-CH(CH3)-CHO

and Both are Optically Inactive becuase no chiral carbon is present

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