473x2 + 5x - 2/3 = 0 find roots
Answers
Answered by
0
Answer:
Basic point: If a,b are the roots of an eqn, then (x-a)(x-b)=0 be that quadratic equation.
If x = 2/3, x = -3 are roots, then the eqn will be
(x-2/3)(x-(-3))=0
⇒ (x-2/3)(x+3) = 0
⇒ x²-(2/3)x+3x-2 = 0
⇒ 3x²-2x+9x-6=0
⇒ 3x²+7x-6=0 is the required eqn.
Compare the eqn with ax²+7x+b=0
Therefore, a=3, b= -6
Similar questions