Math, asked by StarTbia, 1 year ago

4765__ 2,Write the smallest digit and the greatest possible digit in the blank space of each of the given number so that the number formed is divisible by 3.

Answers

Answered by fiercespartan
9

Hey there!

In order to check for the divisibility rule for 3, we will have to add up the digits and check wether the sum is divisible by 3.

4 + 7 + 6 + 5 + x + 2 = 24 + x

the least number is 27, so we will have to add 3 ,

it becomes 27 and is divisble.

the number :- 3

Hope my answer helps!

Answered by mysticd
4

***********************************

We know the divisibility rule :


The given number is divisible


by 3 only when sum of the


digits is a multiple of 3 .


***************************************

Here ,


Let missing digit is x .


Now ,


4765x2 ( if it is divisible by '3'


Sum of all the digits should be


a multiple of 3 .)


4 + 7 + 6 + 5 + x + 2


= 24 + x


Therefore, x should be 0 or


3 , 6, 9


Required " x " value is ,


Smallest digit is ' 0 '


Greatest digit is ' 9 '


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