7221__ 5,Write the smallest digit and the greatest possible digit in the blank space of each of the given number so that the number formed is divisible by 3.
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Answered by
2
these are the following numbers:
a)722195
b)722135
a)722195
b)722135
Answered by
9
Solution :
_________________________
Divisibility Rule of 3 :
A number is divisible by 3 if the Sum
of the digits is divisible by 3 .
_____________________________
Given number 7221 _ 5
Let the required number = x
( 7+2+2+1+x+5 ) should be divisible
by 3
( 17 + x ) divisible by 3 .
smallest number = 1
i.e ( 17 + 1 ) = 18 [ divisible by 3 ]
greatest number ( 17 + 7 ) = 24
[ divisible by 3 ]
Therefore ,
722115 ,
722175 ,
Required blanks are 1 and 7
*****
_________________________
Divisibility Rule of 3 :
A number is divisible by 3 if the Sum
of the digits is divisible by 3 .
_____________________________
Given number 7221 _ 5
Let the required number = x
( 7+2+2+1+x+5 ) should be divisible
by 3
( 17 + x ) divisible by 3 .
smallest number = 1
i.e ( 17 + 1 ) = 18 [ divisible by 3 ]
greatest number ( 17 + 7 ) = 24
[ divisible by 3 ]
Therefore ,
722115 ,
722175 ,
Required blanks are 1 and 7
*****
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