Question

47x and 3y 2 are two three digits numbers. If their product is 1,62,792 find the unknown digits x and y

Answer 1

Answer:

If you multiply 47x and 3y2, the number you get whose digits are as follows:

1, 4 ,(4y+21), (9+7y+3x), (4+yx), 2x

compare these digits with 1,6,2,7,9,2

2x=2, gives x=1, 4+yx=9

In 4+yx, put x=1, you will get y=5

Ans: x=1, y=5