Physics, asked by naushinrahman444, 7 months ago

48. A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds.
The deceleration produced in this case will be :
(a) + 4 m/s2
(b) - 4 m/s2
(c) + 0.25 m/s2
(d) - 0.25 m/s2

Answers

Answered by Anonymous

Answer:

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☆ Given☆

☞Initial velocity of motorcycle =20m/s

☞Final Velocity of motorcycle =0m/s

☞Time taken to come in rest =5sec.

☆To find ☆

☞Deceleration of motorcycle ??

☆Solution ☆

☞ By using 1st equation of Motion

$v = u + at$

☞O =20 +a ×5

☞-20=a ×5

☞a =-20/5=-4m/s

therefore, the deceleration of body is -4m/s.

hence option( b) is correct

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Answered by MяƖиνιѕιвʟє

$\bf{\red{\underline{\bf{Given}}}}$

Initial Velocity (u) = 20 m/s

Final Velocity (v) = 0 m/s

Time (t) = 5 seconds

$\bf{\red{\underline{\bf{ToFind}}}}$

Deceleration (-a)

$\bf{\red{\underline{\bf{Solution}}}}$

We know that,

$\implies Acceleration \: = \frac{Final \: velocity - Initial \: velocity}{Time \: taken} \\ \\ \implies \: a \: = \frac{v - u}{t}$

Put the above given values in it, We get,

$\implies \: a \: = \frac{0 - 20}{5} \\ \\ \implies \: a = \frac{ - 20}{5} \\ \\ \implies \: a \: = - 4m {s}^{2}$

Hence,

➨ a = -4 m/s²

Here,

➨ Negative sign shows deceleration

So,

➨ Option (b) is correct.

➨ Deceleration = -4m/s²

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48. A motorcycle is being driven at a speed of 20 m/s when brakes are applied to bring it to rest in five seconds.The deceleration produced in this case will be :(a) + 4 m/s2(b) - 4 m/s2(c) + 0.25 m/s2(d) - 0.25 m/s2​