Question

48. Four identical cells each having emf E and internal resistance r are connected in series to form
a loop ABCD as shown in figure . Find potential difference.across AB and AC.​

Answer 1

Dear Tanisha,

◆ Answer -

V(AB) = E/2

V(AC) = -E

● Explaintion -

All cells are connected in series, hence total resistance will be -

Req = r + r + r + r

Req = 4r

As one cell is connected with opposite polarity, total EMF is given by -

Eeq = E + E + E - E

Eeq = 2E

Now potential difference across AB is given by -

1/E(AB) = 1/E + 1/(E+E-E)

E(AB) = E/2

Now potential difference across AC is given by -

E(AC) = -E

Hope this helped you. Keep asking.

Answer 2

Answer and explanation given in image.