Question

48
If each resistance in the fig. is of 9 ohm then reading
of the ammeter is :-
(1) 5 A
(2) 8 A
(3) 2 A
(4) 9 A​

Answer 1

Answer:

Sorry for the first... Is this okk now???

Answer 2

The reading of ammeter in given diagram is - (1) 5 A.

In the given question, resistors are connected in parallel.

For the resistors connected after ammeter, collective resistance will be -

1/R= 1/9*5

R= 9/5 ohm.

Now, again parallel circuit will be made, for combination of 5 resistors and 4 resistors.

Ammeter is connected with 5 resistors.

As it is known, voltage across parallel connection remains same, and current in series connection remains same.

Hence, according to the formula. V=IR, current will be calculated.

I= V/R

I= 9/(9/5)

I= 5A.

Thus, ampere reading for given circuit will be 5A.