Question

48³-30³-18³ Evaluate​

Answer 1

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ANSWER

48³-30³-18³

=77760

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Answer 2

Answer:

Given:-

Evaluate​ 48³-30³-18³

Solution:-

Here, we are noticing that this equation is in the form of a³ +b³ +c³

Here we will a³+b³+c³ = 3abc, alzebric identity.

Here,

a³  = 48³

b³  = -30³

c³ = -18³

⇒ $a^{3}+b^{3} +c^{3} = 3abc.$

⇒ $(48)^3 - (30)^3 - (18)^3$ = 3 × 48 × (-30) × (−18)

=  77760

Required Answer =  77760

Explanation:-

Some Alzebric identity are :-

(a+b+c)²= a²+b²+c² +2ab+2bc+2ca

(a+b-c)²=a²+b²+c² +2ab-2bc-2ca

a² +  b²=½ [(a+b)²+(a-b)²]

a³-b³=(a-b)³ +3ab(a-b)