48km/hकी चाल से चलने वाली 100मीटर लम्बी रेलगाड़ी विपरीत दिशा मे जाती हुई 80km लम्बी गाड़ी को 6second मे पार करती है ।दूसरी गाड़ी की चाल होगा।
Answers
Answered by
8
x-48=180÷6
X=30+48
X=78km/h
X=30+48
X=78km/h
Answered by
5
Answer:
Speed of the second train is 136.67 m/s if the length of the train is 800 m
Step-by-step explanation:
Speed of one train = 48 km/h = 48*1000/3600 = 48*5/18 = 40/3 m/s
Relative Speed of the train = Speed of one train + Speed of other Train ( because two trains are running in opposite direction)
Time taken to cross the train = 6 seconds
Distance Traveled = 100 m + 800 m (length of second train is wrong it has to be 800 or 80, solving this problem by taking relevant data 800 m
= 900 m
Use formula,
Speed = Distance/ time
s1+s2 = 900 /6
40/3 + s2 = 150
s2= 150 - (40/3)
= 136.66 m/s
Speed of the second train is 136.67 m/s if the length of the train is 800 m
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