Question

49. Acceleration-time graph for a particle is given in
figure. If it starts motion at t = 0, distance travelled
in 3 s will be

(1) 4 m
(2) 2 m
(3) o
(4) 6 m.​

Answer 1

Answer:

1

st

second

distance traveled=ut+

2

1

at

2

=0+

2

1

×2×1×1=1m

v=u+at,v=0+2×1=2m/s

2

nd

second

s=ut=2×1=2m

3

rd

second

s=ut+

2

1

at

2

=2×1×−

2

1

×2×1×1=2−1=1m

Total distance=4m

Answer 2

Answer:

1st second

distance traveled=ut+1/2at²

:- 0+1/2×2×1×1= 1m²

v=u+at,v=0+2×1=2m/s

2 nd second

s=ut=2×1=2m

3rd second

s=ut1/2at² =2×1×- 1/2×2×1×1 = 2-1 = 1m

total distance :- 4m