Physics, asked by divibhardwaj09, 11 months ago

49. Assuming Bohr's model for Li** atom, the first
excitation energy of ground state of Li** atom is
(1) 10.2 eV
(2) 91.8 eV
(3) 13.6 eV
(4) 3.4 eV

Answers

Answered by qwsuccess
14

Assuming Bohr's model for Li** atom, the first excitation energy of ground state of Li** atom is equal to 91.8 eV.

  • The first excitation energy of the ground state of a Li** atom signifies the transition form n=1 to n=2.
  • The energy of the nth orbit of Li** atom is equal to -13.6*z²/n², where z = 9.
  • The energy for n=1 and n=2 are -122.4 eV and -30.6 eV respectively.
  • The excitation energy is equal to -30.6-(-122.4) = 91.8 eV.
Similar questions