49.If the length of a seconds pendulum is increased by 2% Then in a day the pendulum ------
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T = 2π √(L/g)
ΔT / T * 100 = 1/2 * ΔL/L * 100
= 1/2 * 2% = 1%
Time period increases by 1% =>
So one second becomes 1.01 seconds. The pendulum loses 0.01 sec.
In one day of 86400 seconds, the clock loses 864 seconds. or 144 minutes or 2 hours 24 minutes.
ΔT / T * 100 = 1/2 * ΔL/L * 100
= 1/2 * 2% = 1%
Time period increases by 1% =>
So one second becomes 1.01 seconds. The pendulum loses 0.01 sec.
In one day of 86400 seconds, the clock loses 864 seconds. or 144 minutes or 2 hours 24 minutes.
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