Question

49 P cube by minus 7 Root over 7 p square ​

Answer 1

49p(p+1)(p-1)

Step-by-step explanation:

⇒$49p^3-7\sqrt{(7p)^2}$

⇒$49p^3-7\times 7p$

⇒$49p^3-49p$

⇒$49p(p^2-1)$

⇒49p(p+1)(p-1).

Answer 2

The simplified expression is $-\sqrt{7} p^{2}$

Step-by-step explanation:

The given expression is :

$\frac{49p^{3} }{-7\times\sqrt{7p^{2} } }$

We will factorized 49

$\frac{7\times7p^{3} }{-7\times\sqrt{7p^{2} } }$

7 is common in both denominator and numerator, so it will cancel out.$=\frac{7p^{3} }{-\sqrt{7p^{2} } }\\=\frac{7p^{3} }{-\sqrt{7 }p }\\\\=\frac{7p^{2} }{-\sqrt{7 } }\\\\=\frac{\sqrt{7}\times\sqrt{7} p^{2} }{-\sqrt{7 } }\\\\=-\sqrt{7} p^{2}$

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Simplify

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