Question

49 points question

Plz answer fast

Answer both the questions.

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Answer 1

Step-by-step explanation:

uplod image I think helpful you this answer

Answer 2

Answer:

$we \: have \: \\ \\ {x}^{2} + {y}^{2} < 25 \\ \\ \\ change \: itno \: equation \\ \\ {x}^{2} + {y}^{2} = 25 \\ \\ maximum \: value \: is \: 4 \\ \\ we \: can \: take \: (3 \: and \: 4) \: and \:( 4 \: and \: 3) \\ \\ (x \: and \: y) \equiv( - + 1)( + - 2)( + - 3)( + - 4) \\ \\ \\ number \: of \: ways \: chose \: to \: x = 9 \\ \\ number \: of \: ways \: chose \: to \: y = 9 \\ \\ ways \: of \: chose \: both = 9 \times 9 = 81 \\ \\ possible \: points \: \\ \\ ( + - 3 \: and + - + 4) \\ \\ ( + - 4 \: and + - 3) \\ \\ ( + - 4 \: and \: + - 4) \\ \\ \: here \: number \: of \: points = 12 \\ \\ \: but \: 12 \: points \: for \: {x}^{2} + {y}^{2} \geqslant 25 \\ \\ so \: for \: {x}^{2} + {y}^{2} < 25 are \\ \: number \: of \: reqired \: points = 81 - 12 = 69 \: \\ \\ it \: is \: your \: answer$