Question

49. The equivalent weight of metal whose 1 g carbonate
on heating gives 0.6 g of metal oxide, is
(1)25g
(2) 30 g
(3) 35 g
(4) 40 g​

Answer 1

Answer:

25g??????????????????¿

Answer 2

Answer:

(1) 25g

Explanation:

We are given that

Weight of metal carbonate=1 g

Weight of metal oxide=0.6 g

Weight of carbon dioxide formed=$1-0.6=0.4 g$

We have to find the equivalent  weight of metal

Molecular mass of $CO_2=44 g$

Equivalent mass of $CO_2=\frac{44}{2}=22 g$

So, the carbonate which  releases 22 g of carbonate is equal to equivalent mass of metal carbonate.

So, 0.4 g carbon dioxide  releases from 1 g of metal carbonate

22 g of carbon dioxide will be  released from =$\frac{1}{0.4}\times 22=55 g$ of metal carbonate

Equivalent mass of metal carbonate= 55 g

Molecular mass of carbonate ion= 60 g

So, equivalent mass of carbonate ion=$\frac{60}{2}=30 g$

Therefore, equivalent mass of metal=55-30=25g.

Answer:(1) 25g