49 to the power 15-1 is exactly divisible by
Answers
Still have a question? Ask your own!
What is your question?
6 ANSWERS

Vipin Chaurasia, former Senior Executive at KPMG India (2015-2017)
Answered Mar 26
49^15–1
Well, we can do it intuitively.
For a number which ends with 9 (Special Property of 9)
If power is even, last digit of the number is 1. (9*9=81)
If power is odd, last digit of the number is 9. (9*9*9=729)
Now we know that 49 ends with 9 and 15 is an odd number
Hence, we can conclude that the last digit of 49^15 is 9. (AN ODD NUMBER)
Now deducting 1 from an odd number makes it an even number.
All even numbers can be divided by 2
Your answer is 2
Thanks
49¹⁵ - 1 is exactly divisible by 48 , 24 , 16 , 12 , 8 , 6 , 4 , 3 , 2
Step-by-step explanation:
49¹⁵ - 1
= (7²)¹⁵ - 1
= 7³⁰ - 1
= (8 - 1)³⁰ - 1
= 8³⁰ + ³⁰C₁ * 8²⁹(-1)¹ +..........................................+³⁰C₂₉*8(-1)²⁹ + (-1)³⁰ - 1
= 8³⁰ - 30 * 8²⁹ +..........................................- 30*8 + 1 - 1
= 8³⁰ - 30 * 8²⁹ +..........................................- 30*8
8 is common factor in all
Hence 49¹⁵ - 1 is exactly divisible by 8
Similalrly 7³⁰ - 1 = (6 + 1)³⁰ - 1 will have 6 as common factor
Hence 7³⁰ - 1 is exactly divisible by 6
LCM of 8 & 6 = 24
49¹⁵ - 1
= (48 + 1)¹⁵ - 1
will have all factors of 48 hence exactly divisible by 48
Learn more:
if a 10 digit number 2094x843y2 divisible by 88 then the value of (5x ...
https://brainly.in/question/11094736
If n3 is multiple of 2, then n is divisible by 2. Prove by any method ...
https://brainly.in/question/12244932