Question

490 gm of KCLO3(s) is heated to form KCL & O2 I) find mass of KCL produced ii) find volume of O2 gas at 300K & 2atm pressure​

Answer 1

Explanation:

KClO3 decomposes into KCl and O2 . If the volume of O2 obtained in this reaction is 1.12 L at STP , the weight of KCl formed in the reaction is:

2KClO3 → 2 KCl + 3O2 Here if the volume of O2 at STP is 1.12 L, then at STP 1 mol gas will have volume 22.4 L, so 1.12 L must have 122.4 × 1.12 = 1.1222.40