Question

49p^3 by - 7√7 p^2
divide..............................
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Answer 1

Answer:

$\frac{49p^{3}}{-7\sqrt{7} p^{2}}=-\sqrt{7} p$

Step-by-step explanation:

$\frac{49p^{3}}{-7 \sqrt{7} p^{2}}\\=\frac{7\sqrt{7}\times \sqrt{7} p^{3-2}}{-7 \sqrt{7} }\\=-\sqrt{7} p$

Therefore,

$\frac{49p^{3}}{-7\sqrt{7} p^{2}}=-\sqrt{7} p$

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