Question

49x²-14x+1-64a²+16ab-b², Factorize the given equation.

Answer 1

(49x^2-14x+1)-(64a^2-16ab+b^2)

(7x-1)^2. - ( 8a - b )^2

((7x - 1 + 8a - b ) (7x - 1 - 8a + b)

Answer 2

Answer:

( 7x-1+8a-b )( 7x-1-8a+b )

Step-by-step explanation:

*********************************

We know the algebraic identities:

i ) a² - 2ab + b² = ( a - b )²

ii ) x² - y² = ( x + y )( x - y )

**************†*******************

49x²-14x+1 - 64a²+16ab-b²

= 49x²-14x+1 - ( 64a²-16ab+b² )

= [(7x)²-2(7x)×1+1²]-[(8a)²-2(8a)b+b²]

= ( 7x - 1 )² - ( 8a - b )²

= [(7x-1 )+(8a-b)][(7x-1)-(8a-b)]

= ( 7x-1+8a-b )( 7x-1-8a+b )

••••