Math, asked by pavithrajanani2008, 1 month ago

(4a^2_3b^2)^2+(3b^2-4a^2)^2​

Answers

Answered by Anonymous
1

Answer:

Given, (4a+3b)2−(4a−3b)2+48ab.

We know, (a+b)2=a2+2ab+b2

and (a−b)2=a2−2ab+b2.

Then,

(4a+3b)2−(4a−3b)2+48ab

=((4a)2+2(4a)(3b)+(3b)2)−((4a)2−2(4a)(3b)+(3b)2)+48ab

=(4a)2+2(4a)(3b)+(3b)2−(4a)2+2(4a)(3b)−(3b)2+48ab

=24ab+24ab+48ab

=48ab+48ab

=96ab.

Answered by anjanareddy2009
0

Answer:

Given, (4a+3b)

2

−(4a−3b)

2

+48ab.

We know, (a+b)

2

=a

2

+2ab+b

2

and (a−b)

2

=a

2

−2ab+b

2

.

Then,

(4a+3b)

2

−(4a−3b)

2

+48ab

=((4a)

2

+2(4a)(3b)+(3b)

2

)−((4a)

2

−2(4a)(3b)+(3b)

2

)+48ab

=(4a)

2

+2(4a)(3b)+(3b)

2

−(4a)

2

+2(4a)(3b)−(3b)

2

+48ab

=24ab+24ab+48ab

=48ab+48ab

=96ab.

Step-by-step explanation:

maybe this helps you

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