(4a^2_3b^2)^2+(3b^2-4a^2)^2
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Answered by
1
Answer:
Given, (4a+3b)2−(4a−3b)2+48ab.
We know, (a+b)2=a2+2ab+b2
and (a−b)2=a2−2ab+b2.
Then,
(4a+3b)2−(4a−3b)2+48ab
=((4a)2+2(4a)(3b)+(3b)2)−((4a)2−2(4a)(3b)+(3b)2)+48ab
=(4a)2+2(4a)(3b)+(3b)2−(4a)2+2(4a)(3b)−(3b)2+48ab
=24ab+24ab+48ab
=48ab+48ab
=96ab.
Answered by
0
Answer:
Given, (4a+3b)
2
−(4a−3b)
2
+48ab.
We know, (a+b)
2
=a
2
+2ab+b
2
and (a−b)
2
=a
2
−2ab+b
2
.
Then,
(4a+3b)
2
−(4a−3b)
2
+48ab
=((4a)
2
+2(4a)(3b)+(3b)
2
)−((4a)
2
−2(4a)(3b)+(3b)
2
)+48ab
=(4a)
2
+2(4a)(3b)+(3b)
2
−(4a)
2
+2(4a)(3b)−(3b)
2
+48ab
=24ab+24ab+48ab
=48ab+48ab
=96ab.
Step-by-step explanation:
maybe this helps you
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