4a^2+b^2+4ab+8a+4b+4
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/* We know the algebraic identity:
x²+y²+z²+2xy+2yz+2zx = (x+y+z)². */
Now ,
4a²+b²+4ab+8a+4b+4
= 4a²+b²+4+4ab+4b+8a
=(2a)²+b²+2²+2*2a*b+2*b*2+2*2*2a
= (2a+b+2)²
= (2a+b+2)(2a+b+2)
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