Question

4a + 2ab - 3c , 5ab + 3c - 2a and 3a - 7ab + 2c

Answer 1

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

Answer 2

Step-by-step explanation:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c