ABCD is an isosceles trapezium prove that ABCD is cyclic.
please help.
Answers
Answered by
4
∠A + ∠C = 180° (Sum of the opposite angles of a cyclic quadrilateral is 180°) ∠B + ∠C = 180° (AB || CD) (Sum of the alternate angles of a cyclic quadrilateral is 180″) ∠A + ∠C = ∠B + ∠C ∴ ∠A = ∠B ∴ ABC’D is an isoceles trapezium.
Hope it help
Mark me as brainlist ❣️
Answered by
2
Answer:
An isosceles trapezium is always cyclic.
An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)
An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)PS = QR (property of trapezium)
An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)PS = QR (property of trapezium)PF = QE ( perpendicular distance between two parallel lines remains same irrespective of the point of measurement along the line )
Similar questions