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ABCD is an isosceles trapezium prove that ABCD is cyclic.

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Answers

Answered by khanshadaab70
4

∠A + ∠C = 180° (Sum of the opposite angles of a cyclic quadrilateral is 180°) ∠B + ∠C = 180° (AB || CD) (Sum of the alternate angles of a cyclic quadrilateral is 180″) ∠A + ∠C = ∠B + ∠C ∴ ∠A = ∠B ∴ ABC’D is an isoceles trapezium.

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Answered by Ashvi075
2

Answer:

An isosceles trapezium is always cyclic.

An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)

An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)PS = QR (property of trapezium)

An isosceles trapezium is always cyclic.∠PFS = ∠QER (by construction - both are right angles at the feet of the perpendiculars)PS = QR (property of trapezium)PF = QE ( perpendicular distance between two parallel lines remains same irrespective of the point of measurement along the line )

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