Question

4a2 - 12ab +9b2 - 4c2
do factorisation method.


ANSWER IS =
(2a-3b-2c) (2a-3b+2c) ​

Answer 1

Step-by-step explanation:

(2a-3b)^2 -(2c)2

=> (2a-3b-2c)(2a-3b+2c)

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Answer 2

Explanation:

$4a^{2} - 12ab + 9b^2 - 4c^2$

$= [(2a)^2 - 2(2a)(3b) + (3b)^2] - (2c)^2$

$= (2a - 3b)^2 - (2c)^2$ [because $a^2 - 2ab + b^2 = (a-b)^2$]

=$(2a - 3b - 2c)(2a - 3b + 2c)$ [because $a^2 - b^2 = (a+b)(a-b)$]

Answer: (2a-3b-2c)(2a-3b+2c)

I hope this answer helps. :)