4a² - 9b² - 2a - 3b
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4a² - 9b² - 2a - 3b
write the first two terms in perfect square:
= (2a)² - (3b)² - (2a + 3b)
Apply (a² - b²) = (a + b)(a - b):
= (2a + 3b) (2a - 3b) - (2a + 3b)
Take out common factor (2a + 3b):
= (2a + 3b) [ (2a - 3b) - 1 ]
Evaluate the second bracket:
= (2a + 3b)( 2a - 3b - 1)
Answer: (2a + 3b)( 2a - 3b - 1)
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