Question

4a² - (b - c²) factorise​

Answer 1

Answer:

4a²+b²+c²+4ab-2bc-4ac

= (2a)²+b²+(-c)²+2*(2a)*b+2*b*(-c)+2*(-c)*(2a)

= (2a+b-c)²

Now,

Square root of 4a²+b²+c²+4ab-2bc-4ac

= \sqrt{(2a+b-c)^{2}}

= (2a+b-c)