Question

4a²+b²-c²-d²+4ab+2cd factorise​

Answer 1

Question:

Factorise:4a²+b²-c²-d²+4ab+2cd

Using identity:

$\to$$(a + b)^{2}$$=a^{2} + 2ab + b^{2}$

$\to$$(a - b)^{2} =a^{2} - 2ab +b^{2}$

Solution:

$\to$4a²+ b²- c²- d²+4ab+2cd

$\to$=4$a^{2}$ + 4ab + b² - ( c² + 2cd - d²)

$\to$=$(2a + b)^{2}$ - $( c - d )^{2}$

Answer 2

Answer:

= (2a+b)² - (c-d)² is the correct answer.