Question

4a4-5a2+1 simplify please give solution ​

Answer 1

Step-by-step explanation:

We have 4a⁴-5a²+1

• 4a⁴-4a²-a²+1
• 4a²(a²-1) -1(a²-1)
• (4a²-1)(a²-1)
• (2a-1)(2a+1)(a-1)(a+1). { using x² - y² = (x+y)(x-y) }

Answer 2

Given expression $4a^4-5a^2+1$

What is the middle-term method?

Dividing the middle word into two factors is used in quadratic factorization in this method. In a quadratic factorization employing splitting of the middle term, where x is the product of two factors and the last term is the sum of the two factors,

Now

$4a^4-5a^2+1\\=4a^4-4a^2-a^2+1\\=4a^2(a^2-1)-1(a^2-1)\\=(4a^2-1)(a^2-1)$

Now we use the formula $a^2-b^2=(a+b)(a-b)$, we get

$=(4a^2-1)(a^2-1)\\=[(2a)^2-1^2][a^2-1^2]\\=(2a+1)(2a-1)(a+1)(a-1)$

To learn more about the middle-term method from the given link

https://brainly.in/question/79373

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