Math, asked by mehjabinfirdosh605, 7 hours ago

(4ab + 3cd)²– (4ab – 3cd)²/48
= abcd

Answers

Answered by sharmaaryan14052006

0

see the attachment for ans

mark me as brainliest

Attachments:

Answered by dd973712

0

Step-by-step explanation:

A]

48

(4ab+3cd)

2

−(4ab−3cd)

2

=

48

16a

2

b

2

+9c

2

+24abcd−16a

2

b

2

−9c

2

d

2

+24abcd

=

48

48abcd

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